2x^2-41=5

Solution for 2x^2-41=5 equation:

Simplifying
2x2 + -41 = 5

Reorder the terms:
-41 + 2x2 = 5

Solving
-41 + 2x2 = 5

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '41' to each side of the equation.
-41 + 41 + 2x2 = 5 + 41

Combine like terms: -41 + 41 = 0
0 + 2x2 = 5 + 41
2x2 = 5 + 41

Combine like terms: 5 + 41 = 46
2x2 = 46

Divide each side by '2'.
x2 = 23

Simplifying
x2 = 23

Take the square root of each side:
x = {-4.795831523, 4.795831523}